On Tue, May 13, 2008 at 7:06 AM, James Hartley <[EMAIL PROTECTED]> wrote:
> But if the keys are sorted, I get an error:
> $ cat test1.py
> d = { 'a' : 1, 'd' : 2, 'b' : 3, 'c' : 0 }
>
> for i in d.keys().sort():
> print "%s\t%s" % (i, d[i])
> $ python test1.py
> Traceback (most recent call last):
> File "test.py", line 3, in <module>
> for i in d.keys().sort():
for i in sorted(d.keys()):
or simply
for i in sorted(d):
since iterating a dict gives its keys.
The problem is that the inplace sort() returns None.
d.keys() is a (new) list containing the keys
d.keys().sort() gets the list of keys and sorts it, but the value of
the expression is None, so you are essentially writing
for i in None:
which gives the TypeError you see.
The builtin function sorted() takes any iterable as an argument and
*returns* a sorted sequence so you can use it in an expression.
Kent
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