On Mon, May 19, 2008 at 11:23 PM, W W <[EMAIL PROTECTED]> wrote: > Those examples are really helpful and I'm pretty sure they'll do what > I need, I'll just have to play with them a little more. > > I do have a question about one of the examples though! > > Specifically this part: > > 4 class Operation(threading._Timer): > 5 def __init__(self, *args, **kwargs): > 6 threading._Timer.__init__(self, *args, **kwargs) > 7 self.setDaemon(True) > > So in trying to understand the class definition, I found this: > > "In Python, the ancestor of a class is simply listed in parentheses > immediately after the class name." > > So does that mean that Operation is similar or the same as say: > > Operation = threading._Timer?
No. class Operation(threading._Timer) creates a new class called Operation that inherits from threading._Timer. I.e. threading._Timer is the base class, or superclass, of Operation. Operation = threading._Timer this just makes the name Operation be an alias for threading._Timer; it doesn't create a new class. > Then I'm a little confused by the * and ** - they look just like the > pointer and pointer to a pointer in C++, but do they perform the same > function in python? No, these are not pointers, they allow passing arbitrary lists and dicts of arguments. I don't know of a good writeup of this syntax; here are some pointers: http://bytes.com/forum/thread25464.html Kent _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
