"Kent Johnson" <[EMAIL PROTECTED]> wrote
Assuming the strings are non-overlapping, i.e. the closing "." of onestring is not the opening "." of another, you can find them all with import re re.findall(r'\..*?\.', text)
Hmm, my regex hopelessness comes to the fore again. Why a *? I would probably have guessed the pattern to be \..+?\. What am I missing?Alan G.
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