On Mon, Jun 23, 2008 at 4:06 PM, Dick Moores <[EMAIL PROTECTED]> wrote: > I needed to sort a list of 2-element tuples by their 2nd elements.
We just talked about this: http://thread.gmane.org/gmane.comp.python.tutor/48646/ > I > couldn't see a ready-made function around to do this, so I rolled my own: > > """ > OUTPUT: > [('khaki4', (0, 205, 205)), ('antiquewhite', (16, 78, 139)), ('cyan3', (139, > 131, 120)), ('antiquewhite1', (139, 134, 78)), ('dodgerblue4', (238, 223, > 204)), ('antiquewhite4', (250, 235, 215))] > """ Is that really what you want? You have sorted the second element of the list independently of the first - the order of first elements hasn't changed. > ================================================================== > It works, but did I really need to roll my own? I think I wouldn't have had > to if I understood what arguments to use for either of the built-ins, sort() > or sorted(). Can someone give me a clue? > > BTW what list comprehension would have accomplished the same thing as my > function? If you really want to sort the second element separately, you could use e0_list, e1_list = zip(*alist) e1_list = sorted(e1_list) # Have to use sorted; e1_list is a tuple alist_sorted_by_e1 = zip(e0_list, e1_list) Kent _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
