> Message: 7
> Date: Sun, 24 Aug 2008 00:21:45 +0100
> From: "Alan Gauld" <[EMAIL PROTECTED]>
> Subject: Re: [Tutor] Python open of c:\ path Problem
> To: tutor@python.org
> Message-ID: <[EMAIL PROTECTED]>
> Content-Type: text/plain; format=flowed; charset="iso-8859-1";
> reply-type=original
>
>
> "Wayne Watson" <[EMAIL PROTECTED]> wrote
>
> > junkfile = open('c:\tmp\junkpythonfile','w')
> > IOError: [Errno 2] No such file or directory:
> > 'c:\tmp\\junkpythonfile'
> >
> > I suspect the problem is with the back slash. Comments?
>
> Correct. There are several ways round this, the simplest
> being to use forward slashes which are effectively portable
> across most OSs.
>
> junkfile = open('c:/tmp/junkpythonfile','w')
>
> You could use a raw string by prefixing the string with r
>
> junkfile = open(r'c:\tmp\junkpythonfile','w')
>
>
> Or you could escape the backslash
>
> junkfile = open('c:\\tmp\\junkpythonfile','w')
>
> > BTW, how does one continue a long statement
> > that has, say, a long path to a file?
>
> You can create a long string by adding the shorter string
> elements :
>
> f = open(
> "a:/very/long/path/name/that/needs/a/whole/line/to./itself.py",
> "w")
>
> becomes
>
> f = open("a:/very/long/path/name/" +
> "that/needs/a/whole/" +
> "line/to./itself.py","w")
>
>
> or by using a line continuation character.
>
> f = open("a:/very/long/path/name/" \
> "that/needs/a/whole/" \
> "line/to./itself.py", "w")
>
You don't even need the line continuation character, you can use
implicit line continuation character (since it's inside a parentheses)
f = open("a:/very/long/path/name/"
"that/needs/a/whole/"
"line/to./itself.py", "w")
> HTH,
>
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