2008/9/23 John Toliver <[EMAIL PROTECTED]> > Greetings, > > The book I have says when you anticipate that you will be working with > numbers larger than what python can handle, you place an "L" after the > number to signal python to treat it as a large number. Does this > "treating" of the number only mean that Python won't try to represent > the number internally as a 32bit integer? Python still appears to be > representing the number only with an L behind it so what is happening to > the number then. Is the L behind the number telling python to handle > this large number in HEX instead which would fit into the 32 bit limit? > > thanks in advance, > > John T
The L stands for long integer and means that it will usually use twice the space of a regular integer so in this case 64bits. HTH Adam.
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