On Tue, Sep 23, 2008 at 8:41 PM, Joe Python <[EMAIL PROTECTED]> wrote:
> Hi Pythonistas,
>
> I have a large dictionary of dictionary (50,000+ keys) which has a structure
> as follows:
> DoD = {
> 'flintstones' : {
> 'husband' : "fred",
> 'pal' : "barney",
> 'income' : 500,
> },
> 'jetsons' : {
> 'husband' : "george",
> 'wife' : "jane",
> 'his boy' : "elroy",
> 'income' : 700,
> },
> 'simpsons' : {
> 'husband' : "homer",
> 'wife' : "marge",
> 'kid' : "bart",
> 'income' : 600,
> },
> };
>
> I want to sort the dictionary by 'income'
> Is there an efficient way to do the same.
As has been pointed out, you can't sort a dictionary, it is unordered.
You can sort the list of key, value pairs. The simplest way is to make
a key function that extracts the value on which to sort.
The key, value pairs will look like ('flintstones', {
'husband' : "fred",
'pal' : "barney",
'income' : 500,
)
You want to sort on the 'income' element of the value; this key
function will work:
def key(item):
return item[1]['income']
Then sort with
sorted(DoD.iteritems(), key=key)
Kent
_______________________________________________
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
