Guessing you mean [5,100] as the inclusive interval notation, so all
but the last element of the example pass?
if any(True for x, y in listoflists if 5 <= x and y <= 100):
#do stuff
does this do it for you?
Or if you want to know if any elements of the lists within the larger
list are within the range, and the sublists always have two elements
you could do:
if any(True for x,y in listoflists if 5<= x <=100 and 5<= y <=100):
#do stuff
otherwise, for a list of arbirtary length lists:
from itertools import chain
if any(True for x in chain(*listoflists) if 5<= x <=100):
#do stuff
You can be slightly faster (but less readable) by changing the
if any(...):
to
if [...]:
This is probably more pythonic, as well.
(There might be a better way, but I like itertools).
Hope something in here was helpful...
On 20/10/2008, Srinivas Iyyer <[EMAIL PROTECTED]> wrote:
> dear group,
> a simple question that often challenges me.
>
> I have
>
> I have a list of list:
>
> [[10,45],[14,23],[39,73],[92,135]]
>
> I want to identify if any of the items in this list are in range of [5,100]
>
> These numbers are large in original data, I will be using xrange for memory
> issues.
>
> thank you.
> srini
>
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