<[email protected]> wrote
Ideally, I'd be able to write:
for num in list1:
newlist.append(num+nextnum)
This doesn't work, though because there's no way to access "nextnum"
unless I implement a "count" variable like this:
Or use an iterator:
L = [1,2,3,4,5,6]
i = iter(L)
L2 = [n+i.next() for n in i]
L2
[3, 7, 11]
Is that what you want?
--
Alan Gauld
Author of the Learn to Program web site
http://www.freenetpages.co.uk/hp/alan.gauld
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