You know, that's a great idea :-) Just using options I could keep my initial checks the same (e.g. making sure needed options were included by looking at options.foo) and pass it along without adding much to the query function.
Thanks! _______________________ Samuel Huckins Homepage - http://samuelhuckins.com Tech blog - http://dancingpenguinsoflight.com/ Photos - http://www.flickr.com/photos/samuelhuckins/ AIM - samushack | Gtalk - samushack | Skype - shuckins ________________________________ From: Kent Johnson <ken...@tds.net> To: wormwood_3 <wormwoo...@yahoo.com> Cc: Python Tutorlist <tutor@python.org> Sent: Monday, January 12, 2009 5:09:31 PM Subject: Re: [Tutor] Optional parameter passing On Mon, Jan 12, 2009 at 4:39 PM, wormwood_3 <wormwoo...@yahoo.com> wrote: > Hello all, > > I have used *args and **kwargs to have a function accept optional > parameters, but is there a lazy way to optionally pass parameters? For > example, say my script can accept a number of parameters for a database > connection, such as user, password, and database name. The function that > makes the MySQL call has a default for user, say "root". So if the user > didn't pass in a value for the user option, I don't want to pass it to the > function doing the MySQL call. I don't want to have to do: > > if options.user: > do_mysql_query(user) > else: > do_mysql_query() > > and so on for each possible option. Is there a better way? You would have to put the options into a collection, a list or dict or class. You can use *args and **kwargs at the point of call as well as in a function definition. What about having the defaults in the options object and just passing it to the function? do_mysql_query(options) or pass the options and have the function use code like user = options.user or 'root' Kent
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