"Denis,\n\nThat works perfectly!\n\nMerci Beaucoup!\n\nPayo"
:-)
On Tue, Feb 10, 2009 at 6:48 PM, spir <denis.s...@free.fr> wrote:
> Le Tue, 10 Feb 2009 18:08:26 +0100,
> pa yo <payo2...@gmail.com> a écrit :
>
>> Novice programmer here.
>>
>> I am using urllib.urlencode to post content to a web page:
>>
>> ...
>> >>Title = "First Steps"
>> >>Text = "Hello World."
>> >>Username = "Payo2000"
>> >>Content = Text + "From: " + Username
>> >>SubmitText = urllib.urlencode(dict(Action = 'submit', Headline = Title,
>> >>Textbox = Content))
>> >>Submit = opener.open('http://www.website.com/index.php?', SubmitText)
>>
>> This works fine to produce in this:
>>
>> "Hello World From Payo2000"
>>
>> ...on the page.
>>
>> However I can't work out how to add a linefeed (urlencode: %0A) in
>> front of Username so that I get:
>>
>> "Hello World.
>> From: Payo2000"
>>
>> Any hints, tips or suggestions welcome!
>
> In python (and many other languages) some special characters that are not
> easy to represent have a code:
> LF : \n
> CR : \r
> TAB : \t
> So just add \n to to first line to add an eol: Text = "Hello World.\n"
> [Beware that inside python \n actually both means char #10 and 'newline',
> transparently, whatever the os uses as 'newline' code for text files. Very
> handy.]
> Alternatively, as you seem to be used to web codes, you can have hexa
> representation \x0a or even octal \012
>
> Denis
> -----
> la vida e estranya
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