"Kent Johnson" <ken...@tds.net> wrote in message
news:1c2a2c590902191500y71600feerff0b73a88fb49...@mail.gmail.com...
On Thu, Feb 19, 2009 at 5:41 PM, Dinesh B Vadhia
<dineshbvad...@hotmail.com> wrote:
Okay, here is a combination of Mark's suggestions and yours:
# replace unwanted chars in string s with " "
t = "".join([(" " if n in c else n) for n in s if n not in c])
t
'Product ConceptsHard candy with an innovative twist, Internet Archive:
Wayback Machine. [online] Mar. 25, 2004. Retrieved from the Internet
<URL:
http://www.confectionery-innovations.com>.'
This last bit doesn't work ie. replacing the unwanted chars with " " -
eg.
'ConceptsHard'. What's missing?
The "if n not in c" at the end of the list comp rejects the unwanted
characters from the result immediately. What you wrote is the same as
t = "".join([n for n in s if n not in c])
because "n in c" will never be true in the first conditional.
BTW if you care about performance, this is the wrong approach. At
least use a set for c; better would be to use translate().
Sorry, I didn't catch the "replace with space" part. Kent is right,
translate is what you want. The join is still nice for making the
translation table:
table = ''.join(' ' if n < 32 or n > 126 else chr(n) for n in
xrange(256))
string.translate('here is\x01my\xffstring',table)
'here is my string'
-Mark
_______________________________________________
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
