On Tue, Mar 10, 2009 at 8:45 AM, Harris, Sarah L <sarah.l.har...@jpl.nasa.gov> wrote: > That looks better, thank you. > However I still have a memory error when I try to run it on three or more > files that are over 100 MB?
How big are files in the zip file? It seems that in this line newFile.write(zf.read(zfilename)) the compressed file is unzipped to memory first, then written to the new file. You can read and write in smaller chunks using file objects returned by zf.open(), which take a size parameter. (Maybe it wouldn't work since the file is going to get extracted to memory anyway.) However, the open() method is in Python 2.6, and in Python 2.6 there is also the extractall() method http://docs.python.org/library/zipfile.html#zipfile.ZipFile.extractall which does what you're doing. I'm not sure if it will still cause a memory error. Also, are files in your zip files not in directories, since you're not creating directories? Since this is a learning experience, it might also help creating functions to minimize clutter, or you could familiarize yourself with the language. Moos _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
