Hey Moos/Denis/Kent, Thanks a lot for your replies and suggestions.
Actually the value which I had given was separated by \n\r. I now realized that this cannot be done with one regular expression as there is one limit in negative look behind that it requires fixed width. I guess This limit is there up to python 2.7 version. So actually though I don't want, but I had to do it using splitting :( But thanks a lot for your help, this has given me better understanding the regex. Thanks you all thank you so much. Regards, Kumar On Thu, Apr 9, 2009 at 3:35 AM, Moos Heintzen <iwasr...@gmail.com> wrote: > Hi, > > You can do the substitution in many ways. > > You can first search for bare account numbers and substitute them with > urls. Then substitute urls into <a></a> tags. > > To substitute account numbers that aren't in urls, you simply > substitutes account numbers if they don't start with a "/", as you > have been trying to do. > > re.sub() can accept a function instead of a string. The function > receives the match object and returns a replacement. This way you can > do extra processing to matches. > > import re > > text = """https://hello.com/accid/12345-12 > > 12345-12 > > http://sadfsdf.com/asdf/asdf/asdf/12345-12 > > start12345-12end > > this won't be replaced > start/123-45end > """ > > def sub_num(m): > if m.group(1) == '/': > return m.group(0) > else: > # put url here > return m.group(1) + 'http://example.com/' + m.group(2) > > >>> print re.sub(r'(\D)(\d+-\d+)', sub_num , text) > https://hello.com/accid/12345-12 > > http://example.com/12345-12 > > http://sadfsdf.com/asdf/asdf/asdf/12345-12 > > starthttp://example.com/12345-12end > > this won't be replaced > start/123-45end > > >>> _ > > This is assuming there isn't any <a> tags in the input, so you should > do this before substituting urls into <a> tags. > > > I have super cow powers! > > Moos >
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