spir <denis.spir <at> free.fr> writes: > To avoid that, use non-grouping parens (?:...). This also avoids the need for parens around the whole format: > p = Pattern(r'abc(?:(?!abc).)+jk') > print p.findall(s) > ['abc789jk'] > > Denis
This one works! Thank you Denis. I'll try it out on the actual much longer (multiline) string and see what happens. _______________________________________________ Tutor maillist - [email protected] http://mail.python.org/mailman/listinfo/tutor
