2009/5/31 Nick Burgess <burgess.n...@gmail.com>:
> Got it.
>
> the row is not a string or buffer but the cell is..
>
> for row in spamReader:
> for cell in row:
> if pattern.search(cell):
> print ', '.join(row)
>
>
Alternatively, if you know that the string you want to search for only
appears in a single cell from the row, you could use
for row in spamReader:
if pattern.search(cell[coll_number_here]):
print ', '.join(row)
If there is a range of adjacent cells that could contain the text, you
could try something like
if pattern.search('|'.join(row[3:5])
For non-adjacent cells, try something like
targetCells = [1,3,5]
for row in spamReader:
if pattern.search('|'.join(row[i] for i in targetCells))
Both of these solutions will be faster than iterating over th entire
row, unless tht is specifically what you want.
--
Richard "Roadie Rich" Lovely, part of the JNP|UK Famile
www.theJNP.com
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