On 6/7/2009 8:44 AM Emile van Sebille said...
On 6/7/2009 7:08 AM Gonzalo Garcia-Perate said...
the solution laid somewhere in between:
def within_range(self, n, n2, threshold=5):
if n in range(n2-threshold, n2+threshold+1) and n <
n2+threshold or n > n2 + threshold : return True
return False
Besides the obvious typo you've got there and I cut and paste below.
(+ threshold twice instead of +/- threshold)
Emile
Be careful here -- you probably will get stung mixing ands and ors
without parens.
>>> print False and False or True
True
>>> print False and (False or True)
False
The range test here can only serve to verify n as an integer, so you can
simplify to:
def within_range(self, n, n2, threshold=5):
if n == int(n) and (
n < n2+threshold or n > n2 + threshold) :
return True
return False
Of course, the test in the function is a boolean, so you can return the
result of the boolean directly and eliminate the return True and False
statements:
def within_range(self, n, n2, threshold=5):
return n == int(n) and (
n < n2+threshold or n > n2 + threshold)
Emile
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