Thanks I just happened to find the site myself. I guess I have to pass each character to the function and build the 8-bit ASCII string or is there a better way to do it?
On Tue, Jun 16, 2009 at 3:37 PM, Wayne <[email protected]> wrote: > On Tue, Jun 16, 2009 at 2:25 PM, Tom Green <[email protected]> wrote: > >> Correct 8-bit ASCII. Sorry about that. I am using Python 2.5.2, which >> doesn't support bin. If I upgraded how would I go about converting the >> entire string to 8-bit ASCII? >> >> I appreciate your help. > > > you write the conversion yourself. anks > > > > > 1. # convert a decimal (denary, base 10) integer to a binary string (base > 2) > > 2. # tested with Python24 vegaseat 6/1/2005 > 3. > 4. def Denary2Binary(n): > > 5. '''convert denary integer n to binary string bStr''' > 6. > bStr = '' > 7. if n < 0: raise ValueError, "must be a positive integer" > > 8. if n == 0: return '0' > 9. while n > 0: > > 10. bStr = str(n % 2) + bStr > 11. n = n >> 1 > > 12. return bStr > 13. > 14. def int2bin(n, count=24): > > 15. """returns the binary of integer n, using count number of digits""" > 16. return "".join([str((n >> y) & 1) for y in range(count-1, -1, -1)]) > > 17. > 18. # this test runs when used as a standalone program, but not as an > imported module > 19. > # let's say you save this module as den2bin.py and use it in another > program > 20. # when you import den2bin the __name__ namespace would now be den2bin > and the > > 21. # test would be ignored > 22. if __name__ == '__main__': > 23. print Denary2Binary(255) # 11111111 > 24. > > 25. # convert back to test it > 26. print int(Denary2Binary(255), 2) # 255 > > 27. > 28. print > 29. > 30. # this version formats the binary > > 31. print int2bin(255, 12) # 000011111111 > > 32. # test it > 33. print int("000011111111", 2) # 255 > > 34. > 35. print > 36. > 37. # check the exceptions > > 38. print Denary2Binary(0) > 39. print Denary2Binary(-5) # should give a ValueError > > > from http://www.daniweb.com/code/snippet285.html# > > HTH, > Wayne > >
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