vince spicer wrote:
you can build a dictionary and keep the active key, again this would only
work in predictable data
users = {}
name = None
for line in file:
key, value = [x.strip() for x in line.split(":")]
if key == "name":
name = data[1]
users[name] = {}
else:
users[name][data[0]]
users
{"stefan": {
"id":12345
"color":blue
})
Vince
On Fri, Jul 24, 2009 at 9:39 AM, Stefan Lesicnik <[email protected]> wrote:
Hi Guys,
It seems like this keeps coming up (for me anyways), and i'm never sure how
to do it. I'm very new to programming...
I have a file that has text in a certain format. Lets assume
'''
name: stefan
id: 12345
color: blue
name: joe
id: 54321
color: red
'''
The format is predictable. I understand for non predictable text, you
would have to use pyparser or the like to build a match.
For predictable format, I am never sure how to handle this. I normally use
something like
for line in file:
line.split('\n')
The problem being i dont really do something per line? I would like to say
something like, for line until the next 'name', make that 1 element.
So i would like to then have a list or dict (this probably makes sense for
a dict) with that group. I would then probably split it into various
elements.
So essentially im asking, how do i say the for line until next 'match'.
Would this be something for the re module? Or is there an inbuilt core way?
I hope this makes sense
Thanks!
Stefan
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(Don't top-post. It makes it difficult to see the sequence of responses)
(untested)
users = {}
name = None
for line in file:
key, value = [x.strip() for x in line.split(":")]
if key == "name":
name = value
users[name] = {}
else:
users[name][key] = value
At this point, users is a dictionary keyed by names, and each value is a
dictionary, keyed by 'id' and 'color'
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