[email protected] wrote:
Here is what I have so far:
import os
import csv
countries = {}
reader = csv.reader(open("countries.csv"))
for row in reader:
code, name = row
countries[name] = code
files = set([file for file in os.listdir(os.getcwd()) if file.endswith('svg')])
print len(files)
for file in files:
file = file.strip('.svg')
print file
# if countries.has_key(file):
# print file
When I run this I get:
Flag_of_Uganda
Flag_of_the_United_State
Flag_of_Abkhazia
Flag_of_Montenegro
Flag_of_Qatar
Flag_of_Gabon
Flag_of_Uzbekistan
Flag_of_Kiribati
Flag_of_Armenia
Flag_of_Panama
Flag_of_Monaco
Flag_of_Australia
Flag_of_Liechtenstein
Flag_of_Tunisia
Flag_of_Georgia
Flag_of_Palau
Flag_of_the_Central_African_Republic
...
The problem is that for example the file Flag_of_the_United_States.svg when I
use the strip('.svg') it is returned as Flag_of_the_United_State
Also, How do I remove 'Flag_of', 'Flag_of_the_'
I guess after this I can compare the value with the key and map the tld?
Or is it better to use regex and then search from the list of countries? But
how???
-------- Original Message --------
From: Tim Golden <[email protected]>
Apparently from: [email protected]
To:
Cc: [email protected]
Subject: Re: [Tutor] renaming files within a directory
Date: Sun, 26 Jul 2009 20:41:10 +0100
[email protected] wrote:
OK I am lost ;(
I changed the code to:
reader = csv.reader(open("countries.csv"), delimiter=";")
for row in reader:
... print row
...
['bi', 'Burundi']
['km', 'Comoros']
['dj', 'Djibouti']
['er', 'Eritrea']
...
Now each row is a list with two items each.
But when I do this:
dic = []
for row in reader:
... newdic.append({row[0]: row[1]})
...
dic
[]
I get an empty dictionary
Well, you actually get an empty list :)
To instantiate an empty dictionary, you use curly brackets:
d = {}
To add something to a dictionary, you use:
d[<key>] = <value>
Try something like this:
<code - untested>
import csv
reader = csv.reader(open("countries.csv"), delimiter=";")
countries = {} # note the curly brackets
for row in reader:
code, name = row # handy Python tuple unpacking
countries[name] = code
</code>
Once you're used to the idea, you can get reasonably slick
with dictionary initialisers and generator expressions:
import csv
reader = csv.reader(open("countries.csv"), delimiter=";")
countries = dict ((row[1], row[0]) for row in reader)
And once you're really confident (and if you're a
fan of one-liners) you can get away with this:
import csv
countries = dict (
(name, code) for \
(code, name) in \
csv.reader (open ("countries.csv"), delimiter=";")
)
BTW, I tend to open csv files with "rb" as it seems to
avoid line-ending issues with the csv module. YMMV.
TJG
_______________________________________________
Tutor maillist - [email protected]
http://mail.python.org/mailman/listinfo/tutor
_______________________________________________
Tutor maillist - [email protected]
http://mail.python.org/mailman/listinfo/tutor
Hit send a little early there.
Strip will remove those characters until it hits a character not in the
set. You could use file.split('.svg')[0]
You could also use split to get rid of the Flag_of_ by doing
file = file.split('.svg')[0].split('_')[2]
or you could use replace for it
file = file.split('.svg')[0].replace('Flag_of_', '')
--
Kind Regards,
Christian Witts
_______________________________________________
Tutor maillist - [email protected]
http://mail.python.org/mailman/listinfo/tutor
