On Wed, Aug 19, 2009 at 1:52 AM, Darth Kaboda<[email protected]> wrote: > I'm questioning my reason for why the follwoing code doesn't behave as I > thought it would upon first coding a project. > > m = 8 > n = 10 > cb = [[[0, None]] * (n + 1)] * (m + 1) > cb[3][2][0] = 10 > > This last statement causes the every first element in the list to update. Is > this becuase this method of initializing a list is just a copy of the same > list in memory?
Not literally a copy, but pointing to the same list. The correct term is that each element of the list is a reference, or alias, to the same list. Kent _______________________________________________ Tutor maillist - [email protected] http://mail.python.org/mailman/listinfo/tutor
