Alan Gauld wrote:
<div class="moz-text-flowed" style="font-family: -moz-fixed">
"Olli Virta" <llvi...@gmail.com> wrote
I have a textfile (job.txt) that needs modifying. The structure of
this file
is like this:
AAA1...
BBB1...
CCC1...
AAA2...
BBB2...
CCC2...
etc...
Question is how can I turn this all to a textfile (done.txt) that is
suppose
to look like this:
AAA1...BBB1...CCC1...
AAA2...BBB2...CCC2...
Lots of ways to do it. The simplest is to read the variables line by
line,
so, in pseudo code:
while infile not empty
a = f.readline()
b = f.readline()
c = f.readline()
outfile.write("%s,%s,%s" % (a,b,c) )
If the data is manageable you could read it all into a list then use list
slicing to achieve the same
data = infile.readlines()
for start in range(len(data))[::3]: # get every third index
outfile.write("%s\t%s\t%s" % tuple(data[start :start+3]) )
I suspect you can do even clever things with itertools using groupby
and such, but I'm no itertools expert - its on my list of things to
learn... :-)
HTH,
Between ellipses and etc., you've managed to confuse everyone with the
actual format of your file.
But Alan's response is the closest so far to what I think you might have
had in mind. The thing he seems to be missing is the treatment of newlines.
Basically your output file is just like your input file except that some
newlines have been removed. So the only question is what's the pattern
of removal. You might have a constant number of input lines per group
(e.g. three for your present example). If that's the case, you want to
strip off all newlines except those in front of a multiple of (3). So
loop through the data array, using rstrip() on all the lines except 2,
5, 8, ... You can use the modulo operator (%) to decide whether an
index has the right form.
Alternatively, you might be saying you want a newline whenever the
prefix of the line changes. So loop through the lines, doing the
rstrip() unless the next line begins the same as the present one.
DaveA
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