Kevin Parks wrote:
> def pack(in_seq):
> out_list=[]
> x = 1
> ll=[1, 1]
> for each in in_seq:
> ll[0] = x
> ll[1] = each
> out_list.append(ll)
> #print ll
> x = x + 1
> print out_list
Variable out_list consists of list ll repeated however many times. Each
time you change ll you're changing it everywhere it appears in out_list.
That is, what's being appended to out_list isn't a copy of ll, it's a
pointer to ll.
You need something like:-
out_list.append([ll[0],ll[1]])
And you need to add a return at the end of the function, otherwise it
returns None:
return out_list
--
Michael
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