On 30/09/2009, at 10:44 AM, Luke Paireepinart wrote:
On Tue, Sep 29, 2009 at 11:40 PM, Corey Richardson <kb1...@aim.com>
wrote:
I got suggested to use this format for my code, as it was shorter
and prettier. But It dun work!
if wellness != ["Well","Fine","Good", "OK", "ok", "Ok", "Great",
"Awesome", "Epic"]:
print "Oh, I'm sorry you are not feeling well."
areYouOk = raw_input("I guessed correct, right?")
if areYouOk != ["yes", "yep", "yup", "yea"]:
print "Oh, thats to bad. Things will be better"
else :
print "Oh, I'm glad your ok then!"
It just prints the "Oh, I'm sorry you are not feeling well.", and
then when you reply, it says "Oh, thats to bad. Things will be
better"/
Ahhh! Why does it be do this? And there is no error, btw.
There is no SYNTAX error. That does not mean there is no semantic
error.
A syntax error means your notation is wrong. A semantic error means
you are not asking the computer what you think you are asking it.
In this case you are saying "is their input equal to this list with
many elements?" and the answer is always going to be No because a
string won't be equal to a list unless both are empty.
What you want to be asking is "is this string IN this list somewhere?"
I.E.
if wellness.strip().lower() in ["well", "fine", "good", "whatever"]:
note if you strip & lowercase the list it is far more likely you'll
match your input.
In your case if I typed in "wEll " it would not match "well".
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_______________________________________________
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Hey Corey,
I do believe I recommended this way of doing a conditional, and Rich/
Luke are right, you need to be testing whether or not the string is /
in/ the list, ie:
if wellness not in list_of_wellness_strings:
#do stuff
Luke's use of lower and strip are also good ideas :)
Cheers
--Brett_______________________________________________
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