First I want to thank the following people for your help: Wayne W., Shashwat
A., and Alan G. I appreciate the input/criticism as I continually learn
more and more.
It seems that I am not sure if I am posting correctly to the right thread
and am not sure if it has to do with the fact that I am getting the posts in
a Digest manner. Let me know if you have any suggestions.
Now back to message at hand:
Message: 3
Date: Thu, 5 Nov 2009 21:34:31 -0600
From: Wayne Werner <[email protected]>
To: Katt <[email protected]>
Cc: tutor <[email protected]>
Subject: Re: [Tutor] Change a text string from a list and change it
into an integer number.(WinXP/py2.6.2/Beginner)
<snip>
Currently the above code does not work unless I change the "if" statement
to say:
"if check_year == "c".
It works correctly for me. Try modifying your code:
date = "cyear_11_05"
date2 = date.split("_")
check_year = date2[0]
print check_year
what does that do for you?
-Wayne
For me it prints to the screen the following : cyear
Message: 4
Date: Fri, 6 Nov 2009 09:06:02 +0530
From: Shashwat Anand <[email protected]>
To: Katt <[email protected]>
Cc: tutor <[email protected]>
Subject: Re: [Tutor] Change a text string from a list and change it
into an integer number.(WinXP/py2.6.2/Beginner)
What do you want to say exactly ?
is 'cyear' an integer ?
let's say date1 = "1984_11_05"
Here cyear is just part of a text string which would be in the following:
"cyear_11_05"
My goal(which recent I accomplished with the help of Shashwat A.'s function)
was:
1. Split the string into a list. [cyear,11,5]
2. If date0 == "cyear" then it would replace cyear with the current year
based on the computer's date.
Then it would change this information into an integer and return it.
3. If date0 != "cyear" it would then change the number into an integer and
return the information.
find code that I used below at end of this message.
Then of course you can change it to an integer using following
list-comprehension,
date1 = "1984_11_05"
date1_list = [int(i) for i in date1.split("_")]
date1_list
[1984, 11, 5]
or alternatively,
date1_list_alternate=map(int,date1.split("_"))
date1_list_alternate
[1984, 11, 5]
I am still learning how to work with list comprehensions so I appreciate the
multiple examples using the "for" and "map"
choices.
also your code seems to work on my system.
date = "cyear_11_05"
date2 = date.split("_")
check_year = date2[0]
if check_year == "cyear":
year = localtime().tm_year
else:
year = int(date2[0])
print year
Found that I had not imported localtime from time. It worked once I
discovered this little oversight.
Message: 5
Date: Fri, 6 Nov 2009 09:27:46 +0530
From: Shashwat Anand <[email protected]>
To: Katt <[email protected]>
Cc: tutor <[email protected]>
Subject: Re: [Tutor] Change a text string from a list and change it
into an integer number.(WinXP/py2.6.2/Beginner)
import time
def katt(d):
date0 = d.split("_")[0]
if date0 == "cyear":
return int(time.strftime("%Y"))
else:
return int(date0)
print katt("cyear_11_05")
print katt("1984_11_05")
http://codepad.org/RBjKmNcA
Hope this helps !
Thanks this helps. I actually changed it a little so that I could include
it into another function rather than its own seperate function.
My code is as follows:
if year_check == "cyear":
year = int(strftime("%Y"))
else:
year = int(year_check)
if month_check == "cmonth":
month = int(strftime("%m"))
else:
month = int(month_check)
I of course made sure to include the strftime in my import calls. I may
change the int(strftime("%Y")) for localtime().tm_year because I think I
heard it returns the value as an integer, but will have to experiment.
Thanks again for the inspiration on this section of code.
Thanks again to all.
Katt
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