I find regular expressions alwys hard to get, so here is my solution:
>>> import glob
>>>
glob.glob('C:\\Users\\blueman\\Desktop\\allFiles\\MyTest[0-9].[0-9].zip')
Cheers,
Timo
MARCUS NG schreef:
Hi all,
I am really new to python and I am trying to create a script that
looks at file versions of a particular file
I have 4 files in a folder. One called myTest1.0.zip, myTest2.0.zip,
test3.txt and test4.zip in a directory/folder called allFiles on my
desktop.
so the file structure is as such
C:\Users\blueman\Desktop\allFiles\myTest1.0.zip
and
C:\Users\blueman\Desktop\allFiles\myTest2.0.zip
Aim:
what is the best way to look into the allFiles directory, and only
search the folder for the 2 files myTest1.0.zip and myTest2.0.zip to
extract out only the version numbers 1.0 and 2.0.
what i have for my script so far is
############################
import os
#path of scripts folder
path="C:/Users/blueman/Desktop/allFiles/"
dirList=os.listdir(path)
for fname in dirList:
print fname
############################
so I did think of listing the file names in an array only to realise
that I wouldn't know which index to query if this script is going to
be automated.
what is the best way to obtain the version numbers of the 2 files?
thank you for your time.
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