Alan Gauld wrote:
<div class="moz-text-flowed" style="font-family: -moz-fixed">
"朱淳" <[email protected]> wrote
fileList = []
def openFiles():
for i in range(0,2):
fname = "file%s"%i
f = open(fname,"a")
fileList.append(f)
def closeFiles():
for f in fileList:
f.close()
if __name__=="__main__":
openFiles()
print "fileList
closeFiles()
print fileList
openFiles()
print fileList
I found that after closing files some closed files were left in the
list:
Yes, because you never remove them they will stay there.
If you want to remove them from the list you need you del() them
as part of your close method.
After I call openFiles() and closeFiles() many times, the list will
become fatter and fatter, filled with valueless closed file object. How
could I open the closed file? I can't find the way in python document.
I don't know of a way to open a closed file object, you might want
to store the filename along with the file. Then if you discover it is
closed you can use the name to reopen it.
You could probably just open it again, with:
f = open(f.name, f.mode)
This gives you a new object, which looks like the original one. Notice
that you still have to remove the old object. But that happens
automatically, if you bind the new object to the same name as the old,
or to the same list location. So you could write a reopenfiles()
function, like (untested):
def reopenfiles(fileList):
for i, f in enumerate(fileList):
f = open(f.name, f.mode)
fileList[i] = f
DaveA
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