On Wed, Feb 10, 2010 at 6:47 AM, nikunj badjatya <[email protected]> wrote:
> I commented out the "raise Exception" statement in Row.py library > module. > Here's the (line no. 150 ) of Row.py which i have edited: > > def insert_cell(self, col_index, cell_obj): > if col_index in self.__cells: > if not self.__parent._cell_overwrite_ok: > msg = "Attempt to overwrite cell: sheetname=%r rowx=%d > colx=%d" \ > % (self.__parent.name, self.__idx, col_index) > #raise Exception(msg) > #########*commented to avoid error. > prev_cell_obj = self.__cells[col_index] > sst_idx = getattr(prev_cell_obj, 'sst_idx', None) > if sst_idx is not None: > self.__parent_wb.del_str(sst_idx) > self.__cells[col_index] = cell_obj > > The excel sheet creation code now works fine. > > My question is, Instead of manually goin to /usr/lib/.../row.py and > commenting out the line, Can this be done through few lines of code in > my program itself. ?? Looking at the code above, you can see that the exception is raised only if self.__parent._cell_overwrite_ok is False. So there is an option to allow overwriting. >From the error message it appears that self.__parent is a Worksheet. Looking at the source code for Worksheet.py, the __init__() method does have an optional cell_overwrite_ok= parameter. This parameter is also available in Workbook.add_sheet(). So if you pass cell_overwrite=True to add_sheet() you should be OK. Kent _______________________________________________ Tutor maillist - [email protected] To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
