>>> [x for x in range(3,int((n**0.5)),2)] [] your while loop is an infinite loop. Had you read the range documentations ?
>>> range(3,int((n**0.5)),2) [] >>> n**0.5 1.7320508075688772 >>> n = 3 >>> n ** 0.5 1.7320508075688772 >>> int ( n ** 0.5) 1 >>> range ( 3, 1, 2) [] On Sun, Mar 28, 2010 at 3:38 AM, yd <ydmt...@gmail.com> wrote: > > Having a problem finding the first 1000 prime numbers, here is my code:- > > print(2) > n =3 > counter =1 > while counter <=1000: > for x in range(3,int((n**0.5)),2): > if n%x != 0: > print(n) > n+=1 > counter+=1 > else: > n+=1 > > The problem is, it prints 2 and then does nothing, yet if i try and close, > it says program is still running do you want to kill it, is there a way to > do this with lists, i know python has a prime function but i am not going to > use it because i want to solve this problem without 'cheating'.Thanks. > > > _______________________________________________ > Tutor maillist - Tutor@python.org > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor > >
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