On Tue, Jul 6, 2010 at 8:08 PM, Ken G. <beach...@insightbb.com> wrote:
> Is there a way to sort a dictionary?
>
> Assuming I have a dictionary set containing the following:
>
> {'02': 1, '03': 1, '12': 1, '15': 2, '14': 2, '04': 3, '05': 1, '19': 1,
> '32': 1, '28': 1, '27': 1, '17': 2, '25': 1}
>
> and using the following code:
>
> print ('Printing the result of numbers that are repeated:')
> print
> for x, y in counted.items():
> if y > 1:
> print "Number %s was found %s times." % (x,y)
> # else:
> # print "Number %s was found %s times." % (x,y)
> print
>
> and the result are:
>
> Printing the result of numbers that are repeated:
>
> Number 15 was found 2 times.
> Number 14 was found 2 times.
> Number 04 was found 3 times.
> Number 17 was found 2 times.
>
> and the question is:
>
> How do I sort the dictionary so the numbers listed (15, 14, 04, 17) are
> listed in sorted ascending order such as:
>
> Number 04 was found 3 times.
> Number 14 was found 2 times.
> Number 15 was found 2 times.
> Number 17 was found 2 times.
>
>>> d = {'02': 1, '03': 1, '12': 1, '15': 2, '14': 2, '04': 3, '05': 1,
'19': 1, '32': 1, '28': 1, '27': 1, '17': 2, '25': 1}
>>> import operator
>>> sorted(d.items(), key=operator.itemgetter(1), reverse = True)
[('04', 3), ('17', 2), ('15', 2), ('14', 2), ('25', 1), ('27', 1), ('02',
1), ('03', 1), ('12', 1), ('05', 1), ('19', 1), ('32', 1), ('28', 1)]
~l0nwlf
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