On Sat, Jul 17, 2010 at 13:56, Dave Angel <da...@ieee.org> wrote: > Your code is both far more complex than it need be, and inaccurate in the > stated goal of producing random digits.
Dave, please see the code I posted in this thread more recently, <http://tutoree7.pastebin.com/M1U00vtD>. > There's no need to try to have all the "digits" in memory at the same time. > As others have pointed out, since you're using write() method, there's no > newline automatically added, so there's no problem in writing a few bytes at > a time. I write a 1000 at a time. > Your concern over a leading zero applies equally to two leading zeroes, or > three, or whatever. I don't think so. Look again at my function, randIntOfGivenLength(). Try a for loop with it, say with randIntOfGivenLength(9) and looping 100 times: for x in range(100): n = randIntOfGivenLength(9) n = str(n) print(n) You'll see that all strings have 9 digits. The problem is that none of them begin with "0". These are just strings of almost-random digits, and in the script I give the 1st digit a chance to be a "0" by prepending a digit -- just one -- chosen by random.choice() from the string "0123456789". There's no need for zero-filling. I do agree that it would be good to eliminate the need to use str(). I'll look at the first part of your formatting suggestion, and skip the zero-filling. > So instead of using str() to convert an int to a > string, use string formatting. Either the % operator or the format() > method. Just use a format that guarantees zero-filling to the same width > field as the size limit you supplied. > > So generate a number between 0 and 9999999999, That would be between 1,000,000,000 and 9,999,999,999 . Dick > or whatever, and convert that > to a fixed width string possibly containing leading zeros. Write the string > out, and loop back around. > > DaveA _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
