Mac,
this is what I get:
>>> for prod in itertools.product('ABC', 2):
print(prod)
Traceback (most recent call last):
File "<pyshell#34>", line 1, in <module>
for prod in itertools.product('ABC', 2):
TypeError: 'int' object is not iterable
hmm, what might be that 'int' object? 2?
2010/7/28 ZUXOXUS <zuxo...@gmail.com>
> Sharp thanks, but:
>
> I try to reproduce the example from the table, but:
>
> >>> import itertools
> >>> combinations('ABC', 2)
> Traceback (most recent call last):
> File "<pyshell#27>", line 1, in <module>
> combinations('ABC', 2)
> NameError: name 'combinations' is not defined
> >>>
>
> If im not mistaken, it should return AB, AC, BA, etc.
>
> I'm using Python 3.1
>
>
> 2010/7/28 Mark Lawrence <breamore...@yahoo.co.uk>
>
> On 27/07/2010 23:20, ZUXOXUS wrote:
>>
>>> Hi all pythoners
>>>
>>> I've got a probably easy to answer question.
>>>
>>> Say I've got a collections of strings, e.g.: 'man', 'bat', 'super',
>>> 'ultra'.
>>>
>>> They are in a list, or in a sequence or whatever, say a bag of words
>>>
>>> And now I want to know how many couples I can do with them, and I want
>>> the
>>> program to show me the actual couples: 'manman', 'manbat', 'mansuper',
>>> 'manultra', 'batbat', 'batman', 'batsuper', etc.
>>>
>>> But hey, why building up new words from just two strings? I also want to
>>> know the possible combinations of three words, four words, and perhaps,
>>> why
>>> not, five words.
>>>
>>> So, is it easy to do?
>>>
>>> Sorry, I'm new in programing, and am probably far from being a
>>> math-master
>>>
>>> I'm clueless, I think probably the code have some FOR I IN SEQUENCE...
>>> but
>>> then what? I don't know how to say: take every element and paste it to
>>> another one from the bag, and with another one, and with another one,...
>>>
>>> If it's too complex, I dont need the whole code recipe, just need some
>>> clues, or perhaps a useful link
>>>
>>> Thank you very much in advance!
>>>
>>> _______________________________________________
>>> Tutor maillist - Tutor@python.org
>>> To unsubscribe or change subscription options:
>>> http://mail.python.org/mailman/listinfo/tutor
>>>
>>
>> The lazy way.
>>
>> http://docs.python.org/library/itertools.html
>> Look for combinations().
>>
>> HTH.
>>
>> Mark Lawrence.
>>
>>
>>
>> _______________________________________________
>> Tutor maillist - Tutor@python.org
>> To unsubscribe or change subscription options:
>> http://mail.python.org/mailman/listinfo/tutor
>>
>
>
_______________________________________________
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
http://mail.python.org/mailman/listinfo/tutor
