> Try >>>> print uri.replace('.', '\.') > and you'll find the replacement works fine. > > Or write the output to file, and look at the file. > > Python shows a representation on its prompt, and thus needs to escape the > backslash (by prepending another backslash). Otherwise you might think '\.' > was meant, which is simply a '.'. > But consider: >>>> uri.replace('.', '\n') > 'domain\ncom' >>>> print uri.replace('.', '\n') > domain > com > > because '\n' is really a different string (character) than a backslash + 'n'.
Thanks, that was very helpful. I was using the interactive interpreter to test things. _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor