"Richard D. Moores" <rdmoo...@gmail.com> wrote
So if os.urandom() had been written so that it printed only hex,
b'l\xbb\xae\xb7\x0ft' would have been
b'\x6c\xbb\xae\xb7\x0f\x74' , right?
Yes except that its not urandomthat is printing those values.
urandom returns a string of bytes.
Its the Python interpreter calling the repr() function on
those bytes that is deciding to print either hex or character.
Try this:
'\x6c\xbb\xae\xb7\x0f\x74'
'l\xbb\xae\xb7\x0ft'
print '\x6c\xbb\xae\xb7\x0f\x74'
l╗«À☼t
In the first case its the repr() of the string that gets
printed in the second its the str(). Its the conversion
function that determines what gets printed not urandom()
How were we supposed to know that all the hexes have 2 digits? How
did you?
Simple arithmetic...
Its the hex representation of a byte. A byte is 8 bits long.
A hex digit represents 4 bits (0000-1111) so you need 2 hex digits to
represent 8 bits or one byte.
Alan G.
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