On 11/08/10 02:34, Sudarshana Banerjee wrote:
Hi: I am trying to teach myself Python, and am stuck at the
indentation with the elif statement.
This is what I am trying to type (as copied from the textbook):
x=3
if x==0:
print "x is 0"
elif x&1 ==1:
print "x is a odd number"
elif x&1==0: -- Line 6
print "x is a even number"
If I am combining the if and the print statement, then the elif
statement is in the next line, and all is well with the world. If
however, I write the print as a separate statement, I am getting a
syntax error after I press Enter after keying the first elif statement.
>>> x=3
>>> if x==0:
print x
elif x==2:
Here you have indented the elif statement but it should be at the same
level as the if:
>>> x=3
>>> if x==0:
... print x
... elif x==2:
... print "something else"
...
>>>
SyntaxError: invalid syntax
Again:
>>> x=3
>>> if x==2: print x
elif x&1 == 1: print 'x is odd'
>>> elif x&1 ==0: print 'x is even'
SyntaxError: invalid syntax
I'm not sure what's going on here but the second elif is being
interpreted separate to the rest of the if statement hence a SyntaxError:
>>> elif x&1 == 0: print "x is even"
File "<stdin>", line 1
elif x&1 == 0: print "x is even"
^
SyntaxError: invalid syntax
This works:
>>> if x==2: print x
... elif x&1 == 1: print 'x is odd'
... elif x&1 ==0: print 'x is even'
...
x is odd
If I am pressing two Enters, the code executes; so I have a elif
without a if, and again, a syntax error. What am I not doing right?
Thank you.
Sudarshana.
HTH,
Adam.
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