On 8/21/2010 2:36 PM, Roelof Wobben wrote:
Hello,
I have this programm :
def print_digits(n):
"""
>>> print_digits(13789)
9 8 7 3 1
>>> print_digits(39874613)
3 1 6 4 7 8 9 3
>>> print_digits(213141)
1 4 1 3 1 2 """
count = 0
while n:
count = count + 1
n = n / 10
return count
getal=13789
x=print_digits(getal)
teller=1
while teller <=x :
digit=float(getal/10.0)
digit2=float(digit-int(digit))*10
getal=digit
print int(digit2)
teller=teller+1
But now every digit is placed on another line.
How can I prevent this ?
print int(digit2), # add a comma
Your algorithm is unnecessarily complicated.
You don't need to count first.
You don't need float.
getal=13789
while getal > 0:
getal, digit = divmod(getal, 10)
print digit,
But it is easier to just:
print " ".join(str(getal))
--
Bob Gailer
919-636-4239
Chapel Hill NC
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