>>> I can't work out how to suppress stacktrace printing when exceptions
>>> are thrown.
>>
>> [snip rant]
>>
>> It might have been a good idea to read a tutorial like
>>
>> http://docs.python.org/tutorial/errors.html#handling-exceptions
>
>> or ask before you got annoyed enough to write that rant ;)
>
> Hello,
>
> Thanks for the reply. Stupid me, I just read a half dozen articles on
> the web about python exception handling, including some at
> docs.python. At no point is the 'as' clause discussed as being
> required.
Because 'as' didn't use to be there. That is more recent.
The real difference is between using an 'instance' and a class in the except
clause. You used the former, you need the latter.
> Note that in section 8.3 of that article, the statement is made that
> if the exception matches the the exception type in the following
> format, the statements within the except clause are executed.
>
> except URLError :
> # do something
>
> That in fact, seems to me to be incorrect. It is not my experience
> (e.g., print statements are not executed in the example I gave and the
> sys.exit() is not called).
Have you tried this? In your example, you have
except urllib2.URLError("Badly formed URL") :
which is quite a different thing; and I'm quite sure it's like that in the docs.
If you have tried the above ("except URLError"), I'm curious about an example.
Cheers,
Evert
>
> I'll follow up on your suggestions. I appreciate the help.
>
> Thanks.
>
> mp
>
>> To catch an exception you have to put the class into the except clause, not
>> an instance. Basic example, using 2.6 syntax:
>>
>> WRONG:
>>
>>>>> try:
>> ... 1/0
>> ... except ZeroDivisionError("whatever"):
>> ... print "caught"
>> ...
>> Traceback (most recent call last):
>> File "<stdin>", line 2, in <module>
>> ZeroDivisionError: integer division or modulo by zero
>>
>> CORRECT:
>>
>>>>> try:
>> ... 1/0
>> ... except ZeroDivisionError as e:
>> ... print "caught", e
>> ...
>> caught integer division or modulo by zero
>>
>> Peter
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