"M. 427" <4...@free.fr> wrote
I ended up with this :
Version 3 :
for i,row in d[:].iteritems() : # BUG : TypeError: unhashable type
if len(row) < 2 :
del d[i]
You are getting too complicated.
You don't need the slice and you don't need iteritems.
You have a dictionary. When you iterate over a dictionary
what do you get? Don't know? Try it::
for x in {1:'foo',2:'bar'}: print x
...
1
2
So we get the keys. Now how do we use the keys to get the list?
Standard dictionary access:
print d[1]
foo
You know how to test the lenth of the list and delete the list so put
that together as you did before:
for row in d : # row is actually the key
if len(row) == 1 : # so use the key to get the real row
del row # WRONG #' and delete the row, again using the key
HTH,
--
Alan Gauld
Author of the Learn to Program web site
http://www.alan-g.me.uk/
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