Hello,
Still the same errors Roelof > ---------------------------------------- >> Date: Sat, 25 Sep 2010 19:33:52 +0100 >> Subject: Re: [Tutor] class method problem >> From: andre...@gmail.com >> To: rwob...@hotmail.com >> >> Your method receives 4 arguments and you didn't define one default. >> Try to do something like this: >> >> def find(self, strng=None, ch=None, start=None, stop=None): >> >> Or any other default values that matches your needs. >> >> >> >> On 25 September 2010 19:15, Roelof Wobben wrote: >>> >>> >>> Hello, >>> >>> I have this code: >>> >>> class zoeken() : >>> á ápass >>> á ádef __len__(self): >>> á á á áreturn 0 >>> á ádef __str__(self): >>> á á á áreturn test2 >>> á ádef find(self, strng, ch, start, stop): >>> á á á áindex = start >>> á á á áwhile index < len(strng) and index < stop: >>> á á á á á áif strng[index] == ch: >>> á á á á á á á áreturn index >>> á á á á á áindex += 1 >>> á á á á á áreturn -1 >>> >>> >>> test = zoeken() >>> test.woord = "tamara" >>> test2 = zoeken.find(test, "a", 1,5) >>> print test(test2) >>> >>> But now I get this message : >>> >>> Traceback (most recent call last): >>> áFile "C:\Users\wobben\workspace\oefeningen\src\test.py", line 20, in >>> á átest2 = zoeken.find(test, "a", 1,5) >>> TypeError: find() takes exactly 5 arguments (4 given) >>> >>> I can do zoeken.find (test2,test, "a", 1,5) but then I get this message: >>> >>> Traceback (most recent call last): >>> áFile "C:\Users\wobben\workspace\oefeningen\src\test.py", line 20, in >>> á ázoeken.find( test2, test, "a", 1,5) >>> NameError: name 'test2' is not defined >>> >>> >>> Roelof >>> >>> _______________________________________________ >>> Tutor maillist á- átu...@python.org >>> To unsubscribe or change subscription options: >>> http://mail.python.org/mailman/listinfo/tutor >>> >> >> >> >> -- >> Andreh Palma _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
