On 10/1/10, Steven D'Aprano <st...@pearwood.info> wrote: > On Sat, 2 Oct 2010 01:14:27 am Alex Hall wrote: >> >> Here is my test: >> >> s=re.search(r"[\d+\s+\d+\s+\d]", l) >> > >> > Try this instead: >> > >> > re.search(r'\d+\s+\D*\d+\s+\d', l) > [...] >> Understood. My intent was to ask why my regexp would match anything >> at all. > > Square brackets create a character set, so your regex tests for a string > that contains a single character matching a digit (\d), a plus sign (+) > or a whitespace character (\s). The additional \d + \s in the square > brackets are redundant and don't add anything. Oh, that explains it then. :) Thanks. > > -- > Steven D'Aprano > _______________________________________________ > Tutor maillist - Tutor@python.org > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor >
-- Have a great day, Alex (msg sent from GMail website) mehg...@gmail.com; http://www.facebook.com/mehgcap _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
