What's the best way to model an unfair coin? This is one way to do it, I suppose: Create a list containing only 'H's and 'T's. If you want the coin to have the probability of a head to be 6/11,
['H', 'H', 'H', 'H', 'H', 'H', 'T', 'T', 'T', 'T', 'T'] is the list to use. Use random.choice on the list, for a 6/11 heads probability. See <http://tutoree7.pastebin.com/gxKYkYWW>. That's the only way I can think of. But surely there's a better, more general solution. What if the probability I want is an irrational number, such as 1/e? Sure, I can calculate a fraction that's as close to that irrational number as I want, but.. Am I missing something that's already there in Python 2.6 or 3.1 (the 2 I have)? Dick Moores _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
