"danielle davout" <[email protected]> wrote
I simplify it to
v = u'\u0eb4'
X = (1,)
gen = ((v ,v) for x in X for y in X)
What can be so wrong in this line, around it to give the 1lined file
ໄ:ໄ
where ໄ "is" not u'\u0eb4' but u'\u0ec4' though a direct printing
looks OK
The code will produce a one line file with v repeated twice.
Now why do you think the character is different?
What have you done to check it?
What do you mean by a direct printing?
print v
maybe?
To write the file corresponding to my nth generator of my list h I
use
def ecrire(n):
f= codecs.open("G"+str(n),"w","utf8")
for x, tx in h[n]:
f.write((x + U":"+ tx))
f.write('\n')
Personally I'd use
f.write(U"%s:%s\n" % (x,tx))
but thats largely a matter of style preference I guess.
But why do you have double parens in the first print?
But In its non simplified form
h.append( (x + v + y ,tr[x]+ tr[v]+ tr[y]) for x in CC for y in
OFC) )
before I have a chance to write anything in the file G5
I have got the KeyError: u'\u0ec4'
yes tr is a dictionary that doesn't have u'\u0ec4' as a key
but tr[v] is well definied ...
OK, but the error is valid in that case.
Which implies that you have bad data in CC.
What exactly are you asking?
--
Alan Gauld
Author of the Learn to Program web site
http://www.alan-g.me.uk/
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