Dave Angel wrote: > from math import cos > > JME = 0.4 > L0A = [2.3, 4.65] > L0B = [1.8, 2.2] > L0C = [12.1, 4] > limit = len(L0A) > > L0 = sum(L0A[i]*cos(L0B[i]+L0C[i]*JME) for i in range(limit))
OP, if you are planning to do this "maths on lists" a lot you should have a look at numpy. With numpy Dave's snippet can be written as from numpy import array, cos, sum j = 0.4 a = array([2.3, 4.65]) b = array([1.8, 2.2]) c = array([12.1, 4]) print sum(a*cos(b+c*j)) Peter _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
