On 02/04/2011 11:26 AM, Peter Otten wrote:
Karim wrote:
That is not the thing I want. I want to escape any " which are not
already escaped.
The sed regex '/\([^\\]\)\?"/\1\\"/g' is exactly what I need (I have
made regex on unix since 15 years).
Can the backslash be escaped, too? If so I don't think your regex does what
you think it does.
r'\\\"' # escaped \ followed by escaped "
should not be altered, but:
$ echo '\\\"' | sed 's/\([^\\]\)\?"/\1\\"/g'
\\\\" # two escaped \ folloed by a " that is not escaped
By the way you are right:
I changed an I added sed command for the ' "" ':
karim@Requiem4Dream:~$ echo 'prima " "' | sed -e
's/""/\\"\\"/g;s/\([^\]\)"/\1\\"/g'
prima \" \"
karim@Requiem4Dream:~$ echo 'prima ""' | sed -e
's/""/\\"\\"/g;s/\([^\]\)"/\1\\"/g'
prima \"\"
karim@Requiem4Dream:~$ echo 'prima "Ich Karim"' | sed -e
's/""/\\"\\"/g;s/\([^\]\)"/\1\\"/g'
prima \"Ich Karim\"
karim@Requiem4Dream:~$ echo 'prima "Ich Karim"' | sed -e
's/""/\\"\\"/g;s/\([^\]\)"/\1\\"/g'
prima \"Ich Karim\"
Sorry, for the incomplete command. You pointed it out, many thanks Peter!
Regards
Karim
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