In addition to the wise counsel you've already received, I noticed that your
randint goes from 0 to 10, but you have 20 possible outcomes in dice(). If
I'm counting correctly, it should be roll=random.randint(0, 19).
Tony R.
On Wed, May 11, 2011 at 6:49 AM, Johnson Tran <aznj...@me.com> wrote:
> Hi Guys,
>
> I've been working on a Python program where I create an 8 ball that will
> allow you to ask questions and will reply back with 20 possible answers. It
> will be continuous until the user says quit. My program works fine although
> I am trying to add something more to it, where when the user quits, it will
> present all the answers that the user got again and display them in
> alphabetical order...if anyone could point me in the right direction it'd be
> really helpful...my program so far is : (which works fine with no errros)
>
>
>
> import random
> dice = ("Without a doubt", "It is certain", "It is decidedly so","Yes",
> "For Sure", "No", "Dont count on it", "Try asking again","Reply hazy, try
> again", "Confucious says 'No'", "Better not tell you now","Cannot predict
> now","Concentrate and ask again","My reply is no","Outlook not so
> good","Very doubtful","Outlook is good","Most likely","As I see it, yes","I
> do not understand the question")
> while True:
> choice = raw_input("Type 'ask' to ask a question. Type 'quit' to
> quit.\n")
> if choice == "ask":
> raw_input("Please enter your question:\n")
> roll = random.randint(0, 10)
> print dice[roll]
> raw_input()
> elif choice == "quit":
> True = 0
> raw_input()
> else:
> print "Error -- Try again\n"
>
>
>
>
>
> Thanks,
>
> JT
>
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