"Rayon" <evosw...@hotmail.com> wrote
I am trying to upload a xml file via pycurl, I really need some help here.
So give us a clue. What is wrong with your code? And what does the real code look like, the fragment you have posted doesn't tell us too much - what is c? what have you imported, and how did you do it? Are you getting an error - if so what does it say? Are you getting bad data out? If so what did you get? What did you expect? "I really need some help" doesn't tell us much. -- Alan Gauld Author of the Learn to Program web site http://www.alan-g.me.uk/
url = "https://192.168.0.68/fileupload/upload_file.php"; binaryptr = open('activation.xml','rb').read() head = ['Content-type:text/xml'] c.setopt(c.SSL_VERIFYPEER, 0) c.setopt(c.SSL_VERIFYHOST, 0) c.setopt(c.POSTFIELDS,binaryptr) c.setopt(c.POSTFIELDSIZE,23L) c.setopt(c.HTTPHEADER,head) c.setopt(c.URL, url) c.setopt(c.VERBOSE, 1) c.perform()
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