What is the version of python you are using? >From the documentation of python 2.71. http://docs.python.org/library/functions.html#xrange
CPython implementation detail: xrange() is intended to be simple and fast. Implementations may impose restrictions to achieve this. The C implementation of Python restricts all arguments to native C longs (“short” Python integers), and also requires that the number of elements fit in a native C long. If a larger range is needed, an alternate version can be crafted using the itertools module: islice(count(start, step), (stop-start+step-1)//step). Hope this helps. Thanks and Regards, Sumod On Thu, May 19, 2011 at 6:47 AM, Terry Carroll <carr...@tjc.com> wrote: > Is there any way to use xrange with a start or stop value that exceeds > sys.maxint? > > import sys >>>> print sys.maxint >>>> >>> 2147483647 > >> start = sys.maxint-1 >>>> for i in xrange(start, start+1): >>>> >>> ... pass > ... > >> start = sys.maxint >>>> for i in xrange(start, start+1): >>>> >>> ... pass > ... > Traceback (most recent call last): > File "<stdin>", line 1, in <module> > OverflowError: Python int too large to convert to C long > >> >>>> > Works okay with range, though: > > start = sys.maxint >>>> for i in range(start, start+1): >>>> >>> ... pass > ... > >> >>>> _______________________________________________ > Tutor maillist - Tutor@python.org > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor > -- http://spawgi.wordpress.com We can do it and do it better.
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