I wrote before that I had pasted the function (convertPath()) from my initial post into mycalc.py because I had accidentally deleted it from mycalc.py. And that there was no problem importing it from mycalc. Well, I was mistaken (for a reason too tedious to go into). There WAS a problem, the same one as before.
I now have a hex editor, HxD (<http://mh-nexus.de/en/programs.php>), and have some info to report. I've left convertPath() in mycalc.py, in importable form, and have been experimenting with it in a new module, mycalc2. The first run: def convertPath(path): """ Given a path with backslashes, return that path with forward slashes. By Steven D'Aprano 07/31/2011 on Tutor list """ #>>> path = r'C:\Users\Dick\Desktop\Documents\Notes\College Notes.rtf' #>>> convertPath(path) #'C:/Users/Dick/Desktop/Documents/Notes/College Notes.rtf' import os.path separator = os.path.sep if separator != '/': path = path.replace(os.path.sep, '/') return path gets C:\Windows\System32>python Python 3.2.1 (default, Jul 10 2011, 20:02:51) [MSC v.1500 64 bit (AMD64)] on win32 Type "help", "copyright", "credits" or "license" for more information. >>> import mycalc2 >>> Now I edit it back to its original problem form: def convertPath(path): """ Given a path with backslashes, return that path with forward slashes. By Steven D'Aprano 07/31/2011 on Tutor list >>> path = r'C:\Users\Dick\Desktop\Documents\Notes\College Notes.rtf' >>> convertPath(path) 'C:/Users/Dick/Desktop/Documents/Notes/College Notes.rtf' """ import os.path separator = os.path.sep if separator != '/': path = path.replace(os.path.sep, '/') return path and get C:\Windows\System32>python Python 3.2.1 (default, Jul 10 2011, 20:02:51) [MSC v.1500 64 bit (AMD64)] on win32 Type "help", "copyright", "credits" or "license" for more information. >>> import mycalc2 Traceback (most recent call last): File "<stdin>", line 1, in <module> File "C:\Python32\lib\site-packages\mycalc2.py", line 10 """ SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 144-146: truncated \UXXXXXXX X escape Using HxD, I find that the bytes in 144-146 are 20, 54, 75 or the <space>, 'T', 'u' of " Tutor" . A screen shot of HxD with this version of mycalc2.py open in it is at <http://www.rcblue.com/images/HxD.jpg>. You can see that I believe the offset integers are base-10 ints. I do hope that's correct, or I've done a lot of work for naught. Next I try def convertPath(path): """ Given a path with backslashes, return that path with forward slashes. By Steven D'Aprano 07/31/2011 >>> path = r'C:\Users\Dick\Desktop\Documents\Notes\College Notes.rtf' >>> convertPath(path) 'C:/Users/Dick/Desktop/Documents/Notes/College Notes.rtf' """ import os.path separator = os.path.sep if separator != '/': path = path.replace(os.path.sep, '/') return path and get >>> import mycalc2 Traceback (most recent call last): File "<stdin>", line 1, in <module> File "C:\Python32\lib\site-packages\mycalc2.py", line 10 """ SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 130-132: truncated \UXXXXXXX escape >>> where 130-132 are 20, 30, 37 or the <space>, '0', '7' of " 07/31/2011". So I go with def convertPath(path): """ Given a path with backslashes, return that path with forward slashes. By Steven D'Aprano >>> path = r'C:\Users\Dick\Desktop\Documents\Notes\College Notes.rtf' >>> convertPath(path) 'C:/Users/Dick/Desktop/Documents/Notes/College Notes.rtf' """ import os.path separator = os.path.sep if separator != '/': path = path.replace(os.path.sep, '/') return path and get >>> import mycalc2 Traceback (most recent call last): File "<stdin>", line 1, in <module> File "C:\Python32\lib\site-packages\mycalc2.py", line 10 """ SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 118-120: truncated \UXXXXXXX escape Where 118-120 are 65, 6E, 20, or the 'e', 'n', <space> of "Steven " I then delete that line, and go with def convertPath(path): """ Given a path with backslashes, return that path with forward slashes. >>> path = r'C:\Users\Dick\Desktop\Documents\Notes\College Notes.rtf' >>> convertPath(path) 'C:/Users/Dick/Desktop/Documents/Notes/College Notes.rtf' """ import os.path separator = os.path.sep if separator != '/': path = path.replace(os.path.sep, '/') return path and get >>> import mycalc2 Traceback (most recent call last): File "<stdin>", line 1, in <module> File "C:\Python32\lib\site-packages\mycalc2.py", line 9 """ SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 95-97: truncated \UXXXXXXXX escape where 95-97 are 64, 20, 73 or the 'd', <space>, 's' of "forward slashes" So I delete "forward slashes" and go with def convertPath(path): """ Given a path with backslashes, return that path with >>> path = r'C:\Users\Dick\Desktop\Documents\Notes\College Notes.rtf' >>> convertPath(path) 'C:/Users/Dick/Desktop/Documents/Notes/College Notes.rtf' """ import os.path separator = os.path.sep if separator != '/': path = path.replace(os.path.sep, '/') return path and get >>> import mycalc2 Traceback (most recent call last): File "<stdin>", line 1, in <module> File "C:\Python32\lib\site-packages\mycalc2.py", line 9 """ SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 78-80: truncated \UXXXXXXXX escape where 78-80 are 20, 70, 61 or the <space>, 'p', 'a' of "that path". I then delete that line, and the line above it, and go with def convertPath(path): """ >>> path = r'C:\Users\Dick\Desktop\Documents\Notes\College Notes.rtf' >>> convertPath(path) 'C:/Users/Dick/Desktop/Documents/Notes/College Notes.rtf' """ import os.path separator = os.path.sep if separator != '/': path = path.replace(os.path.sep, '/') return path and get >>> import mycalc2 Traceback (most recent call last): File "<stdin>", line 1, in <module> File "C:\Python32\lib\site-packages\mycalc2.py", line 7 """ SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 20-22: truncated \UXXXXXXXX escape where 20-22 are 68, 29, 3A or the 'h', ')', ':' of "def convertPath(path):" Obviously I can't delete those characters. If you read this far, I thank you. I know it is tedious. But what in the world is going on? Steven asked if convertPath was a problem for Python 2.7. So I put copied mycalc2.py to 2.7.1's site-packages folder and did: def convertPath(path): """ Given a path with backslashes, return that path with forward slashes. By Steven D'Aprano 07/31/2011 on Tutor list """ #>>> path = r'C:\Users\Dick\Desktop\Documents\Notes\College Notes.rtf' #>>> convertPath(path) #'C:/Users/Dick/Desktop/Documents/Notes/College Notes.rtf' import os.path separator = os.path.sep if separator != '/': path = path.replace(os.path.sep, '/') return path Gets C:\Windows\System32>C:\Python27\python Python 2.7.1 (r271:86832, Nov 27 2010, 17:19:03) [MSC v.1500 64 bit (AMD64)] on win32 Type "help", "copyright", "credits" or "license" for more information. >>> import mycalc2 >>> And as he predicted, def convertPath(path): """ Given a path with backslashes, return that path with forward slashes. By Steven D'Aprano 07/31/2011 on Tutor list >>> path = r'C:\Users\Dick\Desktop\Documents\Notes\College Notes.rtf' >>> convertPath(path) 'C:/Users/Dick/Desktop/Documents/Notes/College Notes.rtf' """ import os.path separator = os.path.sep if separator != '/': path = path.replace(os.path.sep, '/') return path C:\Windows\System32>C:\Python27\python Python 2.7.1 (r271:86832, Nov 27 2010, 17:19:03) [MSC v.1500 64 bit (AMD64)] on win32 Type "help", "copyright", "credits" or "license" for more information. >>> import mycalc2 >>> So no problems with convertPath() in 2.7.1 when imported. Dick _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
