On 07-Aug-11 08:37, Kayode Odeyemi wrote:
Hello all,
Please I need help figuring out this permutation.
I have a dict like this:
x = "{'pk': 1L, 'model': 'trans', 'fields': {'updated': 2011, 'tel':
3456}", "{'pk': 2L, 'model': 'trans2', 'fields': {'updated': 2011,
'tel': 34510}";
First of all, that's not a dict. It's just a tuple of strings.
so, when you say:
#loop through and get the keys of each
for k,v in x:
You'll get one iteration, where k=the first string and v=the second.
However, you ignore k and v in all the code that follows, so I'm really
confused what you're trying to do here.
keys = dict(x).keys()
Now you try to create a dict out of a tuple of strings, which won't
quite work as written but in principle would only have created a
dictionary with the first string as the key, and the second as value,
not nested dictionaries.
The dict() constructor really expects to see a sequence of key/value
pairs, so it's going to take your sequence x as a list of two such
pairs, and then raise an exception because the strings are not key/value
pairs. This would succeed if you said
keys = dict((x,)).keys()
perhaps, but it's still not at all what you're trying to accomplish.
print keys
Note that you are re-assigning the value of keys each time through the
loop but printing its last value after the loop exits. Is that what you
intended?
You're expecting Python to take a string that looks like Python source
code and know that you want it to be interpreted as source code.
Instead of using string values, use actual Python syntax directly, like:
x = {
'pk': 1L,
'model': 'trans',
'fields': {
'updated': 2011,
'tel': 3456
}
}
--
Steve Willoughby / [email protected]
"A ship in harbor is safe, but that is not what ships are built for."
PGP Fingerprint 4615 3CCE 0F29 AE6C 8FF4 CA01 73FE 997A 765D 696C
_______________________________________________
Tutor maillist - [email protected]
To unsubscribe or change subscription options:
http://mail.python.org/mailman/listinfo/tutor
