On 2011/08/16 03:10 PM, Timo wrote:
Hello,
Maybe a bit confusing topic title, probably the example will do.
I have a tuple:
t = ('a', 'b', 'c', 'd')
And need the following output, list or tuple, doesn't matter:
(0, 'a', 1, 'b', 2, 'c', 3, 'd')
I tried with zip(), but get a list of tuples, which isn't the desired
output. Anyone with a solution or push in the right direction?
Cheers,
TImo
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>>> t = ('a', 'b', 'c', 'd')
>>> new_t = zip(xrange(len(t)), t)
>>> new_t
[(0, 'a'), (1, 'b'), (2, 'c'), (3, 'd')]
>>> from itertools import chain
>>> list(chain.from_iterable(new_t))
[0, 'a', 1, 'b', 2, 'c', 3, 'd']
That would be for if you were using the zip way, but enumerate should be
simpler as Martin pointed out.
--
Christian Witts
Python Developer
//
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